Lewis Structure of N₂O (Nitrous Oxide)
What is the Lewis structure of N₂O?
N₂O has 16 valence electrons, 4 bonding electron pairs, and 4 lone pairs. N₂O has 16 valence electrons and two major resonance structures. The primary form has two double bonds (N=N=O) with FCs of -1, +1, 0. The secondary form has a triple bond and single bond (N≡N-O) with FCs 0, +1, -1. The molecule is linear.
| Formula | N₂O |
| Name | Nitrous Oxide |
| Total Valence Electrons | 16 |
| Lone Pairs | 4 |
| Has Resonance | Yes |
| Resonance Structures | 2 |
| Concept | Resonance |
| Difficulty | Intermediate |
Step 1: Count Valence Electrons
Each N has 5, O has 6: 5 + 5 + 6 = 16 total.
Step 2: Draw the Skeleton
N-N-O arrangement (nitrogen is NOT the central atom in N₂O because the less electronegative N goes in the middle). Two single bonds use 4 electrons; 12 remain.
Step 3: Distribute Lone Pairs
Distribute remaining electrons to terminal atoms first. After forming multiple bonds, each terminal atom and the central N must satisfy the octet rule.
Step 4: Form Multiple Bonds
Form N=N=O (two double bonds). Terminal N has 2 lone pairs, central N has 0, O has 2 lone pairs. A second resonance structure (N≡N-O) places a triple bond between the nitrogens.
Step 5: Check Formal Charges
- Primary (N=N=O): terminal N = -1, central N = +1, O = 0
- Resonance (N≡N-O): terminal N = 0, central N = +1, O = -1
- Central N has +1 in both structures.
Resonance Structures
N₂O has 2 resonance structures. The actual electronic structure is a hybrid of all resonance contributors.
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