Lewis Structure of NO₂⁻ (Nitrite Ion)
What is the Lewis structure of NO₂⁻?
NO₂⁻ has 18 valence electrons, 3 bonding electron pairs, and 6 lone pairs. NO₂⁻ has 18 valence electrons (17 + 1 for the charge). Two resonance structures exist where the double bond alternates between the two N–O bonds. Brackets with a -1 superscript indicate the overall charge.
| Formula | NO₂⁻ |
| Name | Nitrite Ion |
| Total Valence Electrons | 18 |
| Lone Pairs | 6 |
| Has Resonance | Yes |
| Resonance Structures | 2 |
| Concept | Polyatomic Ion |
| Difficulty | Advanced |
Step 1: Count Valence Electrons
N has 5, each O has 6, plus 1 for the negative charge: 5 + 6 + 6 + 1 = 18.
Step 2: Draw the Skeleton
Nitrogen is central, bonded to two oxygens. Two single bonds use 4 electrons; 14 remain.
Step 3: Distribute Lone Pairs
Distribute: 3 lone pairs on each O (12 e⁻) + 1 on N (2 e⁻) = 14. N only has 6 e⁻ — needs 8.
Step 4: Form Multiple Bonds
Convert 1 lone pair from an O to a π bond: N=O double bond. N now has 8 electrons.
Step 5: Check Formal Charges
- N: FC = 5 - 2 - ½(6) = 0
- O (single bond): FC = 6 - 6 - ½(2) = -1
- O (double bond): FC = 6 - 4 - ½(4) = 0
- Sum = 0 + (-1) + 0 = -1, matching the ion charge.
Resonance Structures
NO₂⁻ has 2 resonance structures. The actual electronic structure is a hybrid of all resonance contributors.
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