Lewis Structure of NO₃⁻ (Nitrate Ion)
What is the Lewis structure of NO₃⁻?
NO₃⁻ has 24 valence electrons, 4 bonding electron pairs, and 8 lone pairs. NO₃⁻ has 24 valence electrons (23 + 1). Three resonance structures exist where the double bond rotates among the three N–O positions. N has FC = +1 and each single-bonded O has FC = -1. The bond order is 1.33.
| Formula | NO₃⁻ |
| Name | Nitrate Ion |
| Total Valence Electrons | 24 |
| Lone Pairs | 8 |
| Has Resonance | Yes |
| Resonance Structures | 3 |
| Concept | Polyatomic Ion |
| Difficulty | Advanced |
Step 1: Count Valence Electrons
N has 5, each O has 6, plus 1 for the charge: 5 + 3(6) + 1 = 24.
Step 2: Draw the Skeleton
Nitrogen is central, bonded to three oxygens. Three single bonds use 6 electrons; 18 remain.
Step 3: Distribute Lone Pairs
Distribute: 3 lone pairs on each O (18 e⁻). N only has 6 — needs 8.
Step 4: Form Multiple Bonds
Convert 1 lone pair from one O into a π bond: N=O. N now has 8 electrons.
Step 5: Check Formal Charges
- N: FC = 5 - 0 - ½(8) = +1
- O (double bond): FC = 6 - 4 - ½(4) = 0
- O (single bond): FC = 6 - 6 - ½(2) = -1
- Sum = +1 + 0 + (-1) + (-1) = -1, matching the ion charge.
Resonance Structures
NO₃⁻ has 3 resonance structures. The actual electronic structure is a hybrid of all resonance contributors.
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