Lewis Structure of O₃ (Ozone)
What is the Lewis structure of O₃?
O₃ has 18 valence electrons, 3 bonding electron pairs, and 6 lone pairs. Ozone has 18 valence electrons and two equivalent resonance structures. In each, the central O has a +1 formal charge and one terminal O has -1. The real structure is a hybrid where both O–O bonds have a bond order of 1.5.
| Formula | O₃ |
| Name | Ozone |
| Total Valence Electrons | 18 |
| Lone Pairs | 6 |
| Has Resonance | Yes |
| Resonance Structures | 2 |
| Concept | Resonance |
| Difficulty | Intermediate |
Step 1: Count Valence Electrons
Each O (Group 6A) has 6 valence electrons: 3 × 6 = 18 total.
Step 2: Draw the Skeleton
The central oxygen bonds to two terminal oxygens. Two single bonds use 4 electrons; 14 remain.
Step 3: Distribute Lone Pairs
Distribute remaining electrons: 3 lone pairs on each terminal O, 1 on central O = 14 electrons used. But central O only has 6 electrons total — needs more.
Step 4: Form Multiple Bonds
Convert one lone pair from a terminal O into a π bond, forming one O=O double bond. The other remains single. This gives the central O an octet.
Step 5: Check Formal Charges
- Central O: FC = 6 - 2 - ½(6) = +1
- Terminal O (single bond): FC = 6 - 6 - ½(2) = -1
- Terminal O (double bond): FC = 6 - 4 - ½(4) = 0
- Two resonance structures exist by swapping which terminal O has the double bond.
Resonance Structures
O₃ has 2 resonance structures. The actual electronic structure is a hybrid of all resonance contributors.
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