Lewis Structure of SO₂ (Sulfur Dioxide)
What is the Lewis structure of SO₂?
SO₂ has 18 valence electrons, 3 bonding electron pairs, and 6 lone pairs. SO₂ has 18 valence electrons and two resonance structures. The double bond alternates between the two S–O bonds, giving each a bond order of 1.5. The central S has FC = +1 and one terminal O has FC = -1.
| Formula | SO₂ |
| Name | Sulfur Dioxide |
| Total Valence Electrons | 18 |
| Lone Pairs | 6 |
| Has Resonance | Yes |
| Resonance Structures | 2 |
| Concept | Resonance |
| Difficulty | Intermediate |
Step 1: Count Valence Electrons
S (Group 6A) has 6, each O has 6: 6 + 6 + 6 = 18 total.
Step 2: Draw the Skeleton
Sulfur is central, bonded to two oxygens. Two single bonds use 4 electrons; 14 remain.
Step 3: Distribute Lone Pairs
Distribute remaining: 3 lone pairs on each O (12 e⁻) + 1 lone pair on S (2 e⁻) = 14. S only has 6 electrons — needs more.
Step 4: Form Multiple Bonds
Convert 1 lone pair from an O to a π bond, forming one S=O double bond. S now has 8 electrons.
Step 5: Check Formal Charges
- S (central): FC = 6 - 2 - ½(6) = +1
- O (single bond): FC = 6 - 6 - ½(2) = -1
- O (double bond): FC = 6 - 4 - ½(4) = 0
- Two resonance structures swap which O has the double bond.
Resonance Structures
SO₂ has 2 resonance structures. The actual electronic structure is a hybrid of all resonance contributors.
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