Lewis Structure of SO₃ (Sulfur Trioxide)
What is the Lewis structure of SO₃?
SO₃ has 24 valence electrons, 4 bonding electron pairs, and 8 lone pairs. SO₃ has 24 valence electrons and three equivalent resonance structures where the double bond rotates among the three S-O positions. Sulfur has FC = +2 and each single-bonded oxygen has FC = -1. The real structure is a hybrid with bond order 1.33.
| Formula | SO₃ |
| Name | Sulfur Trioxide |
| Total Valence Electrons | 24 |
| Lone Pairs | 8 |
| Has Resonance | Yes |
| Resonance Structures | 3 |
| Concept | Resonance |
| Difficulty | Intermediate |
Step 1: Count Valence Electrons
S has 6, each O has 6: 6 + 3(6) = 24 total.
Step 2: Draw the Skeleton
Sulfur is central, bonded to three oxygens. Three single bonds use 6 electrons; 18 remain.
Step 3: Distribute Lone Pairs
Distribute 18 electrons: 3 lone pairs on each O (18 total). S only has 6 electrons from bonds.
Step 4: Form Multiple Bonds
Convert 1 lone pair from one O into a double bond: S=O. S now has 8 electrons. The double bond can be on any of the 3 O atoms, giving 3 resonance structures.
Step 5: Check Formal Charges
- S: FC = 6 - 0 - ½(8) = +2
- O (double bond): FC = 6 - 4 - ½(4) = 0
- O (single bond): FC = 6 - 6 - ½(2) = -1
- Some textbooks use an expanded octet (all double bonds) to minimize formal charges.
Resonance Structures
SO₃ has 3 resonance structures. The actual electronic structure is a hybrid of all resonance contributors.
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